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Let us consider the equation (32) for n = 0:
![\begin{displaymath}
{\bf N} {\bf U}_{0} = 0.\end{displaymath}](img210.gif)
With accordance to equation (23), this is a linear algebraic
equation with degenerate matrices. It may be solved only in
the case when
is an eigenvector.
We restrict ourselves with the situation when the eiconal
equation for P-waves is valid. In this case, the eigenvector is
so vector
can be
expressed in the form
. In
order to specify the amplitude A0 let us consider the
equation (32) for n = 1:
| ![\begin{displaymath}
{\bf N U}_{1} = {\bf M} (A_{0} \nabla \tau_{P})\end{displaymath}](img214.gif) |
(34) |
But any vector
can be decomposed into the sum
where
. Both vectors
and
are eigenvectors connected with eigenvalues
and
correspondently, therefore,
![\begin{displaymath}
{\bf N U}_{1} \equiv {\bf N} (A_{1} \nabla \tau_{P} + {\bf
Q}) \equiv (\mu \mid {\nabla \tau_P} \mid^{2} - \rho) {\bf
Q}\end{displaymath}](img221.gif)
We see that the left side of the equation (34) is
orthogonal to the vector
. It means that
equation (33) can be resolved if and only if
| ![\begin{displaymath}
\nabla \tau_{P} \cdot M\ ( A_{0} \nabla \tau_{P} ) = 0\end{displaymath}](img222.gif) |
(35) |
Inserting expression in equation (33) into the last equation, we use the
property of the operator
, if s is the
natural parameter of a ray
, then for
any scalar function
![\begin{displaymath}
\nabla \tau_{P} \cdot \nabla \psi =\frac{1}{v_P} \frac
{d \psi}{ds}\end{displaymath}](img225.gif)
where
means differentiation along the ray that
intersects the given point. After simple manipulation we
derive from equation (35) the transient equation for the amplitude
A = A0/v:
| ![\begin{displaymath}
\frac{dA}{ds} + \frac{1}{2}A[v \triangle \tau_{P} + \frac{
d (\ln \rho {v_P}^2)}{ds}] = 0\end{displaymath}](img227.gif) |
(36) |
which have solution
![\begin{displaymath}
A(s) = \frac{A(0)}{v_P \sqrt{\rho}}
e^{-{1 \over 2} \int_0^s v_P \triangle \tau_{P} ds }\end{displaymath}](img228.gif)
The well-known notion of geometrical spreading
is connected with
by relation
(S.V. Goldin, 1986)
![\begin{displaymath}
v \triangle \tau = d ( \ln {J} /v ) / ds\end{displaymath}](img231.gif)
consequently,
| ![\begin{displaymath}
A(s) = A(0)/ \sqrt{\rho v_{P} {J} }\end{displaymath}](img232.gif) |
(37) |
Analogous formula is true for S-waves.
The equation (37) describes how the amplitude of the senior
discontinuity of a wave is changing along a ray path.
If the value of J is positive in all points of a given ray
, then along the ray
| ![\begin{displaymath}
{\bf U} \sim \frac{A(0)}{\sqrt{\rho v_{P} {J}
}}R_{q_{0}} [t - t(s)]{\bf t}\end{displaymath}](img233.gif) |
(38) |
where
and
is the tangent-vector of the ray. And
if J < 0, then
![\begin{displaymath}
{\bf U} \sim \frac{A(0)}{\sqrt{\rho v_{P}{J}}}
R_{q_{0}, 1}[t - t(s)]{\bf t}\end{displaymath}](img236.gif)
The situation when J = 0 means that
at q'<q0,
.
Next: Fundamental solutions
Up: 4: CONNECTION WITH RAY
Previous: Ray method
Stanford Exploration Project
1/13/1998