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Event attenuation by weighting

Imagine an event that is attenuated, but not removed, by filters $\st S$ and $\st N$.  
 \begin{displaymath}
\begin{array}
{c}
\sv \epsilon_1 = \st S \sv x \\ \sv \epsilon_2 = \st N \sv x,\end{array}\end{displaymath} (94)
where $\sv x$ contains the event, $\st S$ is the signal filter, $\st N$ is the noise filter, $\sv \epsilon_1$ is the response of the event to filter $\st S$,and $\sv \epsilon_2$ is the response of the event to filter $\st N$. 
 \begin{displaymath}
\begin{array}
{c}
\varepsilon_1 = \Sigma \sv \epsilon_1^2 \\ \varepsilon_2 = \Sigma \sv \epsilon_2^2\end{array}\end{displaymath} (95)
is a measure of the power of the filtered events. When getting a least-squares solution for equations such as ([*]) and ([*]), the events included in $\sv x$ will be distributed between signal and noise as $1/\varepsilon_1$ for the signal and $1/\varepsilon_2$ for the noise.

This distribution may be changed by modifying the system of equations. Consider, for example, this system:  
 \begin{displaymath}
\sv 0 
\approx
\left(
\begin{array}
{c}
\lambda \st S \\  \s...
 ...\left(
\begin{array}
{c}
\sv 0 \\ \st N\sv d\end{array}\right).\end{displaymath} (96)
If $\lambda$ is less than 1, $1/\varepsilon_1$ will increase, allowing relatively more of the event into the signal. If $\lambda$ is greater than 1, $1/\varepsilon_2$ will increase, allowing relatively more of the event into the noise. If $\lambda$ is very large, only events that are almost perfectly removed by $\st S$ will be allowed into the signal.

Even for events that are perfectly predicted and removed by filters $\st S$ and $\st N$,the distribution of events may be controlled by the weighting in equation ([*]), which is the prediction equation with the initial estimate of the signal as the data. In this case, the $\lambda$ controls the final distribution of events in the null space of $\st S$ and $\st N$.Once again, if $\lambda$ is less than 1, $1/\varepsilon_1$ will increase, forcing relatively more of the event into the signal. If $\lambda$ is greater than 1, $1/\varepsilon_2$ will increase, forcing relatively more of the event into the noise.

Once again, the weighting in system ([*]) may be thought of in terms of using $\st S\sv s$ and $\st N\sv n$ as levelers. If $\st S\sv s$ is weighted higher than $\st N\sv n$, the least-squares solutions of $\sv s$ and $\sv n$ will be modified since the values of $\varepsilon_1$ and $\varepsilon_2$ are modified. In the unlikely event that either $\st S\sv s$ or $\st N\sv n$ actually becomes zero, the weighting becomes unimportant, since one of the conditions is fit perfectly and no better solution could be found. In practical situations, both $\st S\sv s$ and $\st N\sv n$ will have some residual and can only be minimized.


next up previous print clean
Next: Examples of event distribution Up: Distribution of events not Previous: Distribution of events not
Stanford Exploration Project
2/9/2001