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Synthetic example

Figure 1 shows inline sections through two synthetic surveys, which were created to test 4D seismic processing algorithms. Although they were modeled post-stack, they contain many features observed in 4D field datasets, including different wavelets, random noise, spatially varying static and phase shifts, different time-varying gain functions, and different mute-zones. The two surveys have different bandwidths and signal-to-noise levels to correspond to separate generations of 3D seismic.

 
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Figure 1
Inline sections through two synthetic datasets.
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Figure 2
Best achievable cross-equalization result
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To simulate the effect of production changes, we created base and monitor reflectivity functions by introducing changes along a `reservoir' interval. The best achievable result is shown in Figure 2. This contains only the coherent fluid changes and residual random noise.

A simple cross-equalization flow consists of match-filtering and amplitude balancing. For this synthetic example, we designed the match-filters on a trace-to-trace basis, to remove the spatially-varying static and phase shifts.

Figure 3 shows the filtered survey, ${\bf A
d_1}$ at the same scale as ${\bf d_2}$. The low amplitude of the figure on the left illustrates the characteristic low value of a due to the noise in d1. The result of the low value of a is coherent geological signal leaking through into the difference plot, which is shown in Figure 4. The ratio of energy in these two images corresponds to a value, $\nu \approx 0.61$.

 
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Figure 3
${\bf A
d_1}$ (left) and ${\bf d_2}$ (right) plotted at same scale
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Figure 4
Difference using match-filter amplitudes, $\nu \approx 1.64$.
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Equalizing the energy in this case (using $\nu=1$), produces the poor result shown in Figure 5. The brightest event in this image is no longer the reservoir interval, but rather the event below it. This would cause problems for interpretation.

For this synthetic, we can calculate a value for $\nu$ based on the signal-to-noise levels in the two surveys. This gave us the results shown in Figure 6. Considerably less coherent energy is present in this image than in Figures 4 and 5. Three independent estimates of $\nu$ were 1.3, 1.235 and 1.25 fall close to the calculated theoretical value of $\nu=1.28$.

 
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Figure 5
Difference after equalizing the energy between surveys, $\nu=1$.
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Figure 6
Difference using $\nu=1.28$.
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previous up next print clean
Next: REFERENCES Up: Rickett & Lumley: Amplitude Previous: Amplitude balancing
Stanford Exploration Project
10/3/1997