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Image Depth in ADCIGs

Figure A-1 shows the basic construction to compute the image depth in ADCIGs based on the image depth in SOCIGs. Triangles $ABD$ and $CBD$ are congruent since they have one side common and the other equal because $\vert AB\vert=\vert BC\vert=h_\xi$. Therefore, $\theta=\pi/2-\beta_r+\delta$. Also, triangles AED and FCD are congruent because $\vert AD\vert=\vert CD\vert$ and also $\vert AE\vert=\vert CF\vert$ (, ). Therefore, the angle $\delta$ in triangle $DCF$ is the same as in triangle $AED$. We can compute $\delta$ from the condition

\begin{eqnarray*}
\theta+\delta+\beta_s&=&\frac{\pi}{2},\\
\frac{\pi}{2}-\beta_...
...+\beta_s&=&\frac{\pi}{2},\\
\delta&=&\frac{\beta_r-\beta_s}{2}.
\end{eqnarray*}

The depth of the image point in the ADCIG, from triangle ABC, is therefore
\begin{displaymath}
z_{\xi_\gamma}=z_\xi+z^*=z_\xi+(\mbox{sign}(h_\xi))h_\xi\cot\left(\frac{\pi}{2}-\beta_r+\delta\right).
\end{displaymath} (5)

Replacing the expression for $\delta$ we get, after some simplification (and taking sign$(h_\xi)=-1$)
\begin{displaymath}
z_{\xi_\gamma}=z_\xi+z^*=z_\xi-h_\xi\tan\left(\frac{\beta_r+\beta_s}{2}\right)=z_\xi-h_\xi\tan(\gamma).
\end{displaymath} (6)

mul-sktch17
Figure 1.
Sketch to show the computation of the image depth in an ADCIG.
mul-sktch17
[pdf] [png]


next up previous [pdf]

Next: Residual Moveout in ADCIGs Up: Reproducible Documents Previous: Traveltime of refracted rays

2007-10-24