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To obtain the solution (1), let us assume the
existence of a function basic
, such
that the function f (x) can be represented by a linear combination
of the basis functions, as follows:
|  |
(5) |
The linear coefficients ck can be found by multiplying both
sides of equation (7) by one of the basis functions
(e.g.
). Inverting the equality
|  |
(6) |
where the parentheses denote the dot product, and
|  |
(7) |
gives us the following explicit expression for the coefficients
ck:
|  |
(8) |
Here
refers to the kj component of the matrix,
inverse to
. The matrix
is invertible as long as the
basis set of functions is linearly independent. In the special case of
an orthonormal basis,
reduces to the identity matrix:

Equation (10) is a least-square estimate of the coefficients
ck. For a given set of basis functions, it approximates the
function f in formula (1) in the least-square sense.
Next: Solution
Up: Problem formulation
Previous: Problem formulation
Stanford Exploration Project
9/12/2000