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Plane-wave superposition

Equation (23) can be simply interpreted as plane-wave superposition. To make this clear, we first dispose of the rho filter by means of a definition.  
 \begin{displaymath}
\tilde u (p, \tau ) \eq
\ \it\hbox{rho} ( \tau ) \ {\rm *} \ \bar u ( p, \tau )\end{displaymath} (24)
Equation (24) will be seen to be more than a definition. We will see that $\tilde u (p, \tau )$ can be interpreted as the plane-wave spectrum . Substituting the definition (24) into both (23) and (14) gives another transform pair:  
 \begin{displaymath}
\begin{tabular}
{\vert c\vert} \hline
 \\ $u(x, t)\ =\ \int\...
 ...\ 
 \int u(x, \tau+px)\ dx$\space \\  
 \\  \hline\end{tabular}\end{displaymath} (25)

To confirm that $\tilde u (p, \tau )$ may be interpreted as the plane-wave spectrum, we take $\tilde u (p, \tau )$ to be the impulse function $\delta (p\,-\,p_0 ) \, \delta ( \tau \,-\, \tau_0 )$ and substitute it into the top half of (25). The result $u(x,t) = \delta (t-p_0 x - \tau_0 )$is an impulsive plane wave, as expected.


previous up next print clean
Next: Reflection coefficients spherical versus Up: SLANT STACK Previous: Inverse slant stack
Stanford Exploration Project
10/31/1997