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It seems we can represent a sinusoid by Z-transforms
by setting a pole on the unit circle.
Taking , we have the filter
| |
(25) |
The signal bt seems to be the complex exponential
,but it is not quite that
because bt is ``turned on'' at t = 0, whereas
is nonzero at negative time.
Now, how can we make a real-valued sinusoid starting at t=0?
Just as with zeros, we need to complement the pole at by one at .The resulting
signal bt is shown on the left in Figure 7.
On the right is a graphical attempt to plot the impulse function
of dividing by zero at .
sinus
Figure 7
A pole on the real axis
(and its mate at negative frequency)
gives an impulse function at that frequency
and a sinusoidal function in time.
Next, let us look at a damped case like leaky integration.
Let and .Then .Define
| |
(26) |
| (27) |
The signal bt is zero before
t = 0 and is after t = 0.
It is a damped sinusoidal function
with amplitude decreasing with time as .We can readily recognize this as an exponential decay
| |
(28) |
where the approximation is best for values of near unity.
The wavelet bt is complex.
To have a real-valued time signal,
we need another pole at the negative frequency,
say .So the composite denominator is
| |
(29) |
Multiplying the two poles together as we did for roots
results in the plots of 1/A(Z)
in Figure 8.
dsinus
Figure 8
A damped sinusoidal function of time
transforms to a pole near the real -axis,
i.e., just outside the unit circle in the Z-plane.
Notice the ``p'' in the figure.
It indicates the location of the pole Zp
but is shown in the -plane,
where .Pushing the ``p'' left and right will lower and raise the resonant frequency.
Pushing it down and up will raise and lower the duration of the resonance.
EXERCISES:
- How far from the unit circle are the poles of
1/(1 - .1Z + .9Z2)? What is the decay time
of the filter and its resonant frequency?
Next: Polynomial division
Up: DAMPED OSCILLATION
Previous: DAMPED OSCILLATION
Stanford Exploration Project
10/21/1998