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Next: The substitution operator Up: COSMETIC ASPECT OF WAVE Previous: Spatial scaling before migration

Exponential scaling

Exponential scaling functions have some ideal mathematical properties. Take the Z-transform of a time function at:  
 \begin{displaymath}
A(Z) \eq a_0\ +\ a_1 \,Z\ +\ a_2 \,Z^2\ + \ ...\end{displaymath} (9)
The exponentially gained time function is defined by  
 \begin{displaymath}
\uparrow A (Z) \eq a_0\ +\ a_1 \,e^{\alpha} \,Z\ +\ a_2 \,e^{ 2 \alpha } 
\,Z^2\ +\ ...\end{displaymath} (10)
The symbol $ \uparrow $ denotes exponential gain. Mathematically, $ \uparrow $ means that Z is replaced by $ e^{\alpha} Z $.Polynomial multiplication amounts to convolution of the coefficients:  
 \begin{displaymath}
C(Z) \eq A(Z) \ B(Z)\end{displaymath} (11)
By direct substitution,  
 \begin{displaymath}
\uparrow C \eq ( \uparrow A ) \ ( \uparrow B )\end{displaymath} (12)
This means that exponential gain can be done either before or after convolution. You may recall from Fourier transform theory that multiplication of a time function by a decaying exponential $\exp (- \alpha t)$ is the equivalent of replacing $- i \omega$ by $ - i \omega + \alpha$ in the transform domain.

Specialize the downward-continuation operator $\exp (ik_z z) $ to some fixed z and some fixed kx. The operator has become a function of $\omega$ that may be expressed in the time domain as a filter at. Hyperbola flanks move upward on migration. So the filter is anticausal. This is denoted by  
 \begin{displaymath}
A(Z) \eq 
a_0\ \ +\ \ a_{-1} \ {1 \over Z }\ \ +\ \ a_{-2} \ {1 \over Z^2}\ \ +\ \ ...\end{displaymath} (13)
The large negative powers of Z are associated with the hyperbola flanks. Exponentially boosting the coefficients of positive powers of Z is associated with diminishing negative powers--so $\uparrow A$ is A with a weakened tail--and tends to attenuate flanks rather than move them. Thus $\uparrow A$ may be described as viscous.

From a purely physical point of view cosmetic functions like gain control and dip filtering should be done after processing, say, $\uparrow (AB)$.But $\uparrow (AB)$ is equivalent to ($ \uparrow A)$($ \uparrow B)$,and the latter operation amounts to using a viscous operator on exponentially gained data. In practice, it is common to forget the viscosity and create A($ \uparrow B)$.Perhaps this means that dipping events carry more information than flat ones.


previous up next print clean
Next: The substitution operator Up: COSMETIC ASPECT OF WAVE Previous: Spatial scaling before migration
Stanford Exploration Project
10/31/1997