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2-D TIME EXTRAPOLATION AND ITS CONJUGATE

The acoustic wave equation in two dimensional space is
\begin{displaymath}
{\partial^2 P \over {\partial t^2}} = v^2 ({\partial^2 P \over {\partial x^2}} + {\partial^2 P \over {\partial z^2}})\end{displaymath} (9)
where x and z are the surface and depth axis, respectively. By approximating the derivatives by finite differences, equation (8) becomes

\begin{displaymath}
{1 \over {\Delta t^2}}( P_{i-1,j,k} - 2 P_{i,j,k} + P_{i+1,j,k})\end{displaymath}

\begin{displaymath}
= {v_{j,k}^2 \over {\Delta z^2}}( P_{i,j-1,k} - 2 P_{i,j,k} ...
 ...2 \over {\Delta x^2}}( P_{i,j,k-1} - 2 P_{i,j,k} + P_{i,j,k+1})\end{displaymath} (10)
where i, j and k represent the time, depth and surface indices, respectively. By rearranging for time-extrapolation, we get the following equation
\begin{displaymath}
P_{i+1,j,k} = 2(1-2\alpha_{j,k})P_{i,j,k} + \alpha_{j,k}(P_{i,j-1,k} + P_{i,j+1,k} + P_{i,j,k-1} + P_{i,j,k+1}) - P_{i-1,j,k}\end{displaymath} (11)

\begin{displaymath}
\alpha_{j,k} = {v_{j,k}^2 \Delta t^2 \over {\Delta z^2}}\end{displaymath}

where I assumed $\Delta x = \Delta z$.

The matrix representation of this operator is the same as equation(4) except that the size of each matrix is now larger than the corresponding matrix in equation(4) because I need to express the two-dimensional wavefield with an abstract vector form. For a space of (z,x)=(5,6), the matrix ${\bf T}$ becomes a block tridiagonal matrix as follows :
\begin{displaymath}
{\bf T}=
\left[
\begin{array}
{cccccc}
{\bf R_1}&\bf A&\bf 0...
 ...\bf 0&\bf 0&\bf 0&\bf 0&{\bf A}&{\bf R_6}\\ \end{array}\right],\end{displaymath} (12)
where ${\bf A}$ is a diagonal matrix having the following elements

\begin{displaymath}
\alpha_{j,k} = {v_{j,k}^2 \Delta t^2 \over {\Delta z^2}}.\end{displaymath}

The matrix ${\bf R_k}$ represents a tri-diagonal matrix :
\begin{displaymath}
{\bf R}_k=
\left[
\begin{array}
{ccccc}
2(1-2\alpha_{1,k})&\...
 ...k}\\ 0&0&0&\alpha_{5,k}&2(1-2\alpha_{5,k})\\ \end{array}\right]\end{displaymath} (13)

The conjugate operator can easily be obtained by substitution of the transposed form of the new matrix ${\bf T}$into the equation(7). The code for 2-D algorithm, which has passed dot-product test, can be found in the CD-rom version of this report.


previous up next print clean
Next: Conclusions Up: Ji: Conjugate RTM Previous: Example
Stanford Exploration Project
11/17/1997