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REFERENCES

The expression for the ray velocity in a medium with elliptical velocity dependency is given by the expression
\begin{displaymath}
\frac{1}{V^2 (\alpha)} \ =\ \frac{\cos^2 \alpha }{V_{\parallel}^{2}} +
\frac{\sin^2 \alpha }{V_{\perp}^{2}},\end{displaymath} (9)
where $\alpha$ is the ray angle measured from the axis of symmetry (positive counterclockwise) and $V_{\parallel}$ and $V_{\perp}$ are the velocities in the directions parallel and perpendicular to the axis of symmetry (Figure A-1-a). When the axis of symmetry is vertical, the angle that measures the direction of propagation of the ray with respect to the vertical is the same as the group velocity angle.

When the axis of symmetry is rotated an angle $\gamma$ (Figure A-1-b), the expression for the ray velocity becomes (for the same ray direction):
\begin{displaymath}
\frac{1}{V^2 (\alpha)} \ =\ 
\frac{\cos^2(\alpha - \gamma)}{...
 ...parallel}^{2}} +
\frac{\sin^2(\alpha - \gamma)}{V_{\perp}^{2}} \end{displaymath} (10)

 
tilted-ellipses
tilted-ellipses
Figure 11
Ray velocity as a function of direction in an elliptically anisotropic medium: (a) Axis of symmetry vertical (ray angle = group velocity angle). (b) Axis of symmetry tilted (ray angle = $\alpha$; group velocity angle = $\phi$).
view

where $\alpha - \gamma$ is the angle from the axis of symmetry to the ray (group velocity angle).

If the ray travels a distance d between two points (Figure 1),
\begin{displaymath}
d \ =\ \sqrt{\Delta x^2 + \Delta z^2}\end{displaymath} (11)
the corresponding traveltime t is
\begin{eqnarray}
t^2 & = & 
\frac{(d \cos(\alpha - \gamma))^2}{V_{\parallel}^{2}...
 ...alpha \cos \gamma - d \cos \alpha \sin \gamma )^2}
{V_{\perp}^{2}}\end{eqnarray} (12)

To further simplify this equation we need to know the values of $d \cos \alpha$ and $d \sin \alpha$. In order to do this, we need to be careful about the sign of $\alpha$ (clockwise or counterclockwise) for the given ray direction. We also need to be careful about the sign of $\Delta x$ and $\Delta z$.It turns out that regardless of how the signs of these quantities are defined (as long as they are consistent) the final expression for t2 is always, as expected, the same. The result is
\begin{displaymath}
t^2 \ =\ 
\frac{( -\Delta z \cos \gamma + \Delta x \sin \gam...
 ...elta x \cos \gamma + \Delta z \sin \gamma )^2}
{V_{\perp}^{2}}.\end{displaymath} (13)
This is the expression for the traveltime of a ray that travels between two points separated by a distance d in an homogeneous elliptically anisotropic medium with axis of symmetry forming an angle $\gamma$ with the vertical. This equation is the heart of the inversion procedure proposed in this paper.

In this appendix, I show the expressions for the partial derivatives of the traveltime ti (equation (5)) with respect to the model parameters mk, where mk is a component of the vector m:
\begin{eqnarray}
\mbox{\boldmath$m$} & = & (m_1,...,m_N,m_{N+1},...,m_{2N},m_{2N...
 ...lel_N},
\gamma_1,...,\gamma_N,
b_1,...,b_N,a_1,...,a_N). \nonumber\end{eqnarray}

First, the derivatives with respect to the interval parameters $S_{\perp_j}$, $S_{\parallel_j}$ and $\gamma_j$ ($1 \le j \le N$):
\begin{eqnarray}
\frac{ \partial t_{i} }{\partial m_k} & = &
\left\{
\begin{arra...
 ...}} & \mbox{if $2N+1 \leq k \leq 3N$}\end{array} 
\right. \nonumber\end{eqnarray}
Note that for the interval parameters the derivatives with respect to the jth variable depend only upon the properties of the jth layer.

The derivatives of the traveltime with respect to the boundary parameters (aj and bj), depend on the properties of the medium above and below that boundary, as follows:
\begin{eqnarray}
\frac{\partial t_i}{\partial m_k} & = & 
\left\{
\begin{array}
...
 ...
& \mbox{if $4N+2 \leq k \leq 5N$} \\ \end{array}\right. \nonumber\end{eqnarray}
Since the traveltime ti is not affected by the position of the top boundary, $\frac{\partial t_i}{\partial a_1} \ =\ 
\frac{\partial t_i}{\partial b_1} \ =\ 0$.

When a ray travels horizontally, only the first N components of the vector of partial derivatives are non zero. For the forward modeling this is not problem and it simply means that the horizontal component of the velocity is the only parameter that affects the traveltime of a horizontally traveling ray. Problems arise, however, when we try to invert these traveltimes because there are infinite combinations of the other parameters that satisfy the data equally well (null space). This translates into instability of the inversion procedure. For these reason, this inversion does not use rays that travel exactly along the horizontal.

After making the appropriate simplifications in the above equations for the case of isotropic media, it results a set of equations similar to the ones obtained by Lee (1990). Note two misprints in Lee's equations.

 


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Next: About this document ... Up: Michelena: Anisotropic tomography Previous: ACKNOWLEDGMENTS
Stanford Exploration Project
11/18/1997