For a formal model, we will need definitions.
Simple multiple reflections are generated by 1/(1+*cZ*^{n}),
where *c* is a reflection coefficient and *Z*^{n} is the two-way
traveltime to the water bottom.
We will express reflectivity as an unspecified filter *R*(*Z*),
so the reverberation operator as a whole is 1/(1+*R*(*Z*)),
where *R*(*Z*) is like the adjustable coefficients in a gapped filter.
This form is partly motivated by the idea that 1>|*R*|.
Taking *x*_{t} to denote the
reflection coefficients versus depth
or the multiple-free seismogram, and taking
*y*_{t} to denote the one-dimensional seismogram with multiples,
we find that the relation between them is conveniently expressed with
*Z*-transforms as *Y*(*Z*)=*X*(*Z*)/(1+*R*(*Z*)).

Likewise, we will express the source signature not as a convolution
but as an inverse polynomial
(so designature turns into convolution).
Suppose that source signature as a whole
is given by the operator 1/(1+*S*(*Z*)).
The final data *D*(*Z*)
is related to the impulse-source seismogram *Y*(*Z*)
by *D*(*Z*)=*Y*(*Z*)/(1+*S*(*Z*)).

The trouble with the definitions above is that they are in the Fourier domain.
Since we are planning to mix in the NMO operator,
which stretches the time axis,
we will need to reexpress everything in the time domain.
Instead of *X*(*Z*)=*Y*(*Z*)(1+*R*(*Z*)) and *Y*(*Z*)=*D*(*Z*)(1+*S*(*Z*)),
we will use shifted-column matrices to denote convolution.
Thus our two convolutions can be written as

(2) | ||

(3) |

of amplitude.
Simple theory (energy distributed on the area of an expanding sphere)
suggests that the scaling factor *t*
converts the amplitude of to .So we define a matrix to be a diagonal with the weight *t*
distributed along it.

We need also to include the time shifts of NMO. In chapter we saw that NMO is a matrix in which the diagonal line is changed to a hyperbola. Denote this matrix by .Let be the result of attempting to generate a zero-offset signal from a signal at any other offset by correcting for divergence and moveout:

(4) |

The NMO operator can be interpreted in two ways, depending on whether we plan to find one filter for all offsets, or one for each. In other words, we can decide if we want one set of earth reflection coefficients applicable to all offsets, or if we want a separate reflection coefficient at each offset. From chapter we recall that the more central question is whether to include summation over offset in the NMO operator. If we choose to include summation, then the adjoint sprays the same one-dimensional seismogram out to each offset at the required moveout. This choice determines if we have one filter for each offset, or if we use the same filter at all offsets.

Equation (2) actually refers only to zero offset. Thus it means .Merging this with equations (3) and (4) gives

(5) | ||

(6) |

Now it is time to think about what is known and what is unknown. The unknowns will be the reverberation operators and .Since we can only solve nonlinear problems by iteration, we linearize by dropping the term that is the product of unknowns, namely, the last term in (6). This is justified if the unknowns are small, and they might be small, since they are predictions. Otherwise, we must iterate, which is the usual solution to a nonlinear problem by a sequence of linearizations. The linearization is

(7) |

(8) |

(9) |

Recall that the unknowns are like prediction filters. Everything in that is predictable by and is predicted in an effort to minimize the power in .During the process we can expect to tend to whiteness. Thus our statement of wishes is

(10) |

(11) |

Some years ago I tested this concept on a small selection of data, including Yilmaz and Cumro dataset 27, used in Figure 6. The signature waveform of this dataset was hardly measurable, and almost everything was in the reverberation. Thus, results nearly equal to Figure 6 could be obtained by omitting the deconvolution before NMO. Although I was unable to establish by field-data trials that simultaneous deconvolution is necessary, I feel that theory and synthetic studies would show that it is.

10/21/1998