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## Source line and receiver line interval

In this case the desired fold for a 10 m x 10 m bin is 24. This fold can be decomposed as, say, 6 inline and 4 cross-line. Since the fold cross-line is half the number of receiver lines in the recording patch, this means the recording patch will have 8 receiver lines. The distance between the receiver lines drl can be computed as
 (3)
where is the maximum offset cross-line, 3000 m in this case, and nrl is the number of receiver lines per patch, 8 in this case. This gives drl=400 m.

The source line interval (dsl) can be similarly computed from the expectation that the inline fold be 6.
 (4)
Here nchl is the number of channels per receiver line, 300 in this case (maximum inline offset of 3000 m and receiver interval 20 m), is the receiver interval, 20 m, and Foldx is 6. This gives dsl=500 m. If we wanted to apply the theory of symmetric wavefield sampling we might set dsl=400 m. Here I will not use the symmetric wavefield sampling theory.

Next: Salvo Up: STANDARD GEOMETRY Previous: Maximum offset inline and
Stanford Exploration Project
7/8/2003