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An alternative method

The alternative method we propose first Fourier transforms the time series p(t). Then it applies the traditional log-Fourier transformation (described above) to the spectrum of the original time trace. We call this new domain the Fourier-log-Fourier domain(${\bf FLF}$). We denote $\tau_{1}$ as the variable of the new domain after the original $\alpha$ stretch.

In this domain the intended trace stretch is carried out by a simple scaling of the series' coefficients[*]:  
 \begin{displaymath}
 {P_{1}(\tau_{1})} = {P(\tau_{1}) e^{i \tau_{1} \log{1\over{\alpha}}}}\end{displaymath} (4)

Comparing (2) and (4), we find that the stretching in the ${\bf FL}$ and in the ${\bf FLF}$ domain differ only in the exponantial scaling factor.

The number of samples $n_{\omega}$ for a well sampled representation of our input data in the ${\bf FLF}$ domain is:

 
 \begin{displaymath}
 {n_{\omega}} = {2 f_{\max} t_{\max} \log({f_{\max}\over{f_{\min}}})}.\end{displaymath} (5)

This expression derives directly from equation (3) by interchanging the role of the frequency and time axis. Especially, note the symmetry of the non logarithmic factor of (3) and (5).

3|c|    
3|c|Logarithmic trace stretch - An overview    
3|c|    
Interpolation Log-Fourier transformation FL Fourier-Log-Fourier transformation FLF
    ${\bf F}ourier: p(t) \rightarrow p(\omega)$
  ${\bf L}og:~~~~~~p(t) \rightarrow p(s)$ ${\bf L}og:~~~~~p(\omega) \rightarrow p(\nu)$
  ${\bf F}ourier: p(s) \rightarrow p(\sigma)$ ${\bf F}ourier: p(\nu) \rightarrow p(\tau)$
Interpolation according to (1): $\alpha$ stretch by multiplication: $\alpha$ stretch by multiplication:
              $p(t) \rightarrow p(t_{1})$               $p(\sigma) \rightarrow p(\sigma_{1})$               $p(\tau) \rightarrow p(\tau_{1})$
3|c|Disadvantages    
Each stretch requires a new interpolation. Overhead calculations: FL. Long traces after logarithmic stretch. Comparatively,expensive overhead calculations: FLF.
3|c|Advantages    
Easy to implement. No overhead calculations. Each $\alpha$ stretch is a simple multiplication. Each $\alpha$ stretch is a simple multiplication. Shorter traces in the transform domain.

previous up next print clean
Next: ADVANTAGES Up: SOLUTIONS Previous: The standard answers
Stanford Exploration Project
11/18/1997