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I found that squaring the semblance values produced a better
result than the semblance values themselves. My resulting
cdf function was then
 
(11) 
In addition, I need to account for the fact that I am not scanning over
all possible values. I introduced a constant parameter g_{max}
that scaled my values so that that one standard deviation of might correspond to 25 standard deviations .
Finally, we are going to a precondition the model Fomel et al. (1997) with
the inverse of and solve the problems
in terms of the variable ,
 

 (12) 
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Stanford Exploration Project
5/23/2004