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PS-DMO in the frequency-wavenumber log-stretch domain

The previous section shows a kinematic PS-DMO operator. Like PP-DMO, kinematic PS-DMO can not properly handle phase and amplitude (). (, ) discuss a PS-DMO operator on the f-k domain by using a truncation of power series for the moveout of reflections from dipping reflectors in a constant velocity media.

() discuss that the PP-DMO operator in the f-k domain is computationally expensive because the operator is temporarily non-stationary. He uses the idea of () to express a more accurate PP-DMO operator by a logarithmic time stretching.

() exploit the idea of computational efficiency of the logarithmic time stretching for the PS-DMO operator, however their formulation is not clearly expressed. Therefore, I reformulate their work using the PS-DMO smile presented in the previous section and following a procedure similar to () and (). This operation accounts for constant velocity case.

Starting from the PS wave DMO smile,  
 54#54 (23)
By following Hale's assumption that p0(t0,x,H) = pn(tn,x,H), we obtain the 2D PS-DMO operator in the f-k domain:  
 55#55 (24)
Equation ([*]) implies a change of variable from t0 to tn. Therefore, equation ([*]) becomes  
 56#56 (25)
where
57#57 (26)
Equation ([*]) is the base for PS-DMO in the f-k domain. By using a time log-stretch transform pair,
   58#58 (27)
The DMO operator in the f-k log-stretch domain becomes  
 59#59 (28)
where  
 60#60 (29)
When either kh or 61#61 gets the values of , the filter goes to as well.

The previous expression is equivalent to the one presented by (). Note that equation ([*]) is based on the assumption that p0(t0,x,H) = pn(tn,x,H). This doesn't include changes in midpoint position and/or common reflection point position. This allows for a correct kinematic operator but one with a poor amplitude distribution along the reflectors.

() refers to this problem in the log-stretch frequency wavenumber domain by reformulating Black's f-k DMO operator. This operator is based on the assumption that p0(t0,x0,H) = pn(tn,xn,H). The midpoint location also changes, leading to a more accurate distribution of amplitudes. After implementing the PS-DMO operator (), extending this operator is a feasible task. Following the derivation used by (), I state a more accurate PS-DMO operator in the log-stretch frequency wavenumber domain. This new operator differs from the previous one in the filter 62#62. The new filter is  
 63#63 (30)

This filter reduces to if kh=0 or kH if 64#64.

Note that for a value of 65#65, the filter reduces to the known expression for P waves data ().

Figure [*] shows a series of impulse responses for this operator in the frequency domain.

 
imps
imps
Figure 2
Impulse responses for the DMO operator, PP case (left), PS case (right)
[*] view burn build edit restore

Figure [*] shows the same series of impulse responses as Figure [*] but with the new filter [equation ([*])]. Both operators create the same kinematic response. However, Figure [*] shows that the filter in equation ([*]) gives a more accurate amplitude distribution along the impulse response.

We can trust the PS results since the PP impulse response, obtained with the filter in equation ([*]) and 65#65, is the same as that obtained by (). Moreover, the amplitude distribution follows Jaramillo's result.

 
imps-new
imps-new
Figure 3
Impulse responses for the new PS-DMO operator, PP case (left), PS case (right)
[*] view burn build edit restore


next up previous print clean
Next: Real data Up: Prucha and Biondi: STANFORD Previous: PS-DMO smile derivation
Stanford Exploration Project
6/7/2002