() discuss that the PP-DMO operator in the f-k domain is computationally expensive because the operator is temporarily non-stationary. He uses the idea of () to express a more accurate PP-DMO operator by a logarithmic time stretching.
() exploit the idea of computational efficiency of the logarithmic time stretching for the PS-DMO operator, however their formulation is not clearly expressed. Therefore, I reformulate their work using the PS-DMO smile presented in the previous section and following a procedure similar to () and (). This operation accounts for constant velocity case.
Starting from the PS wave DMO smile,
54#54 | (23) |
55#55 | (24) |
56#56 | (25) |
57#57 | (26) |
58#58 | (27) | |
59#59 | (28) |
60#60 | (29) |
The previous expression is equivalent to the one presented by (). Note that equation () is based on the assumption that p0(t0,x,H) = pn(tn,x,H). This doesn't include changes in midpoint position and/or common reflection point position. This allows for a correct kinematic operator but one with a poor amplitude distribution along the reflectors.
() refers to this problem in the log-stretch frequency wavenumber domain by reformulating Black's f-k DMO operator. This operator is based on the assumption that p0(t0,x0,H) = pn(tn,xn,H). The midpoint location also changes, leading to a more accurate distribution of amplitudes. After implementing the PS-DMO operator (), extending this operator is a feasible task. Following the derivation used by (), I state a more accurate PS-DMO operator in the log-stretch frequency wavenumber domain. This new operator differs from the previous one in the filter 62#62. The new filter is
63#63 | (30) |
This filter reduces to if kh=0 or kH if 64#64.
Note that for a value of 65#65, the filter reduces to the known expression for P waves data ().
Figure shows a series of impulse responses for this operator in the frequency domain.
Figure shows the same series of impulse responses as Figure but with the new filter [equation ()]. Both operators create the same kinematic response. However, Figure shows that the filter in equation () gives a more accurate amplitude distribution along the impulse response.
We can trust the PS results since the PP impulse response, obtained with the filter in equation () and 65#65, is the same as that obtained by (). Moreover, the amplitude distribution follows Jaramillo's result.