Footnotes

$\begin{displaymath} s_y=g_y\Leftrightarrow {k_m}_y=0 \end{displaymath}$

$\begin{displaymath} k_z\equiv {k_z}_x\end{displaymath}$

$\begin{displaymath} {k_z}_0\equiv {{k_z}_x}_0\end{displaymath}$

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$\begin{displaymath} \v k_z= \sqrt{\v_0^2 {k_z}_0^2 +{k_m}_x\left(\v_0^2-\v^2\right)} \end{displaymath}$

$\begin{displaymath} \omega= \sqrt{\omega_0^2+{k_m}_x\left(\v_0^2-\v^2\right)} \end{displaymath}$

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Stanford Exploration Project
10/25/1999